0.1x^2-11x+100=0

Solution for 0.1x^2-11x+100=0 equation:

0.1x^2-11x+100=0

a = 0.1; b = -11; c = +100;
Δ = b2-4ac
Δ = -112-4·0.1·100
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-9}{2*0.1}=\frac{2}{0.2}
=10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+9}{2*0.1}=\frac{20}{0.2}
=100
$